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stelthii

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Posts posted by stelthii

  1. I think we will reach the door. Only that we will do it in infinite amount of moves.

    Spoiler

     

    Let S = distance left to the door, then the first move will be = S x (1/2).

    In regards to the total distance we'll end up with an equation of: S = 1/2 + 1/4 + 1/8 + 1/16... 1/n. There are infinite middle points/moves between us and the door, so we'll always traverse half of half.

    At the same time, if we combine the above with common sense, then we know that we will (eventually) reach the door.

    In the end, we'll reach the door, but with infinite points of "moves".

     

     

  2. cl_maxpackets, snaps and rate as qbd said are the usual suspects. Their values might be too low, the default values however are not that bad.

    So, does this happen in every server? Is it consistent?

    I see the lagometer on your video has some small, probably negligible spikes. Check cl_packetdup and +1 its value, it might help with the overall connection stability as well.

    Substanz and Doge like this
  3. The result I'm getting at is 33.

    Spoiler

     

    We sum the two parts of equation 1 with the respective two parts of equation 2. At the end we get a new equation:

    A + 2A - 4B + 7B +2C - 5C = 16 + 83 => 3A + 3B - 3C = 99 (3)

    At this point we notice that equation 3 that we just got, looks a lot like the riddle's last equation. We can use the common coefficient 3 as common factor for the 1st part. 2nd part is similar:

    3 x (A + B - C) = 3 x 33 => A + B - C = 33

     

     

    Substanz and JillyJill like this
  4. One day at noon, 2 people who have never seen each other meet at the city's center and decide to have lunch together. One of them is the father of the other person's daughter.

    How is that possible?

     

    SOLVED

     

    Click on the spoiler below to reveal the correct answer.

    Spoiler

    They are blind.

     

    JillyJill likes this
  5. @Substanz You're correct! I didn't expect that solution also.

    @Teddy Your reasoning(binary code) while not right, happens to make your execution both completely correct and optimal(lowest number of tosses while 100% fair)!

    You're both technically correct with both answers having their pros and cons. Apologies, but I can't choose a winner, I leave it up to you.

    JillyJill likes this
  6. 7 hours ago, JillyJill said:

    I think we could use a little hint. Does she actually throw this coin or does something else with it?

    When there's "luck", "coin" and "probability" in the same context, then yes, it's almost always assumed that there's a coin toss. So you're completely right. :)

    The above is not a hint though, so I'll provide one below:

    Spoiler

    As we know, a coin has only 2 sides. A single coin toss can only represent 2 outcomes (example: Heads = Dress1, Tails = Dress2). Pay attention to the word in bold. :)

     

  7. A woman needs a new dress and so she enters a store. Upon trying many dresses, she likes 3 of them the most. She can't decide between the 3 and ends up leaving it to luck, so she reaches for her purse and takes out a single coin.

    Using that coin only, how can she pick a dress randomly while being fair (equal probability for each of the 3 choices)?

    Good luck!

     

    SOLVED

     

    Click on the spoiler below to reveal the correct answer.

    Spoiler

    Started with the common purpose that we need to choose a dress using toss (yes/no) for each dress :

    Positive way (we find a direct tree to the goal) :

    3 (from) > 3 (yes) > 2 (yes) > 1(yes)

    or gives :

    3 > 1 (means 2 no at first shot)

    or gives :

    3 > 2  > 1

    So 9 moves for a first direct approach to the goal, that we can x3 to let a chance to each entity to get its tree ^^ = 27 moves for something fair (let's close the eyes and take one dress randomly, it's easier ^^)

     

    Alternative way:

    Assuming that she knows binary code i would think she converts the head and number to 0 and 1. now she toss the coin 2 times. she can get 00, 01, 10, and 11.

    00 - first dress

    01 - second dress

    10 - third dress

    11 - try again

    thats equal chance for each - 25%

     

    Substanz and JillyJill like this
  8. Answer is 100 (if we assume that the images of green apples in equation 2 & 3 = 2 apples, instead of 1.5).

    Spoiler

     

    Equation 1: 3x = 90 => x = 30 (Red Apple = 30)

    Equation 2: x + 2y + 2y = 230 => 4y = 200 => y = 50 (Green Apple = 50)

    Equation 3: z + 2y + x = 210 => z + 100 + 30 = 210 => z = 80 (Yellow Apple = 80)

    Equation 4: y - x + z = A => 50 - 30 + 80 => A = 100

     

     

    JillyJill and Substanz like this
  9. I fully support collectibles as a concept. It goes to show how much someone has liked a certain game by getting said achievement.

    However, I don't like that each developer implements this system in their own way. Sometimes it ends up being a great addition to the gameplay and story, other times it results in a glorified annoyance of a feature.

    I really liked the way Ori and the Blind Forest implemented collectibles. Each one acquired offered a small "power-up" for the character. Their distribution in the map was in such a way that it was easily deductible that X area had something "extra" (a collectible or a sealed off shortcut between areas etc). Finding them didn't always mean that you could get it, as some required a to-be-unlocked ability and/or a little puzzle. By the end, I had collected them all and explored the map in its entirety.

    JillyJill likes this
  10. Hey people!

     

    Some may know/noticed already, but Steam summer sales for 2019 are live for a few hours now. As with every year's sales, the shop is buzzing with many upon many heavy discounts for some really amazing games. It's a great time for many gamers to stock up on games, as well as explore hidden gems that would have been overlooked in any other occasion..

     

    Therefore, this is a great opportunity to recommend those games that you believe everyone should buy and give a try. Even more now that there is an awesome offer to take advantage of!

     

    I'm looking forward to everyone's answers and who knows, maybe besides the suggestions, you'll discover some worthwhile games yourselves from the other posts.

     

    So.. What are the offers that stand out for you, noNamers, and what are you looking to buy?

    Roohansama, JillyJill and Substanz like this
  11. The non sarcasm version of what Finny said is that a rule needs to pass two conditions (in my opinion):

     

    1) Being intuitive.

    2) Easy to enforce.

     

    A small and simple rule set is the best anywhere. Rules that even a brand new player will follow instinctively because they're based on regular common sense. Secondly, any rule will fail fast if the admins cannot make sure it is being enforced at any time. It becomes completely useless. A lot of glitches and spots as well as 333 fps are forbidden on Nuke sniper. I can tell you that this rule's enforcement is pretty hard. I cannot even begin to imagine how we could check about your rule if it were to become a thing. Impossible. ^^

     

    Feel free to check the current rules and I bet you'll see yourself how true the above points are. One of the things that I like best about nN servers is this. Very few, simple rules anyone can read, understand and follow. Results in a welcoming server that has something for everyone to have their fun there. :)

    Roohansama, G4b1t, Substanz and 3 others like this
  12. Seconding what Scrappy said. When you get inexplicable vsync-like issues it's always one of the three: power mode, win10 shenanigans, gpu driver options.

     

     

    the issue is that nvidia panel is in greek and i cant find v sync option

    Μα τα Ελληνικά είναι εύκολα και κατανοητά!/s

     

    Ορίστε αγαπητέ:

    image.png

     

    Runny likes this
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